Antoine-vergelyking

${\displaystyle \log _{10}p=A-{\frac {B}{C+T}}\quad \Rightarrow \quad p=10^{\left(A-{\frac {B}{C+T}}\right)}\quad \Rightarrow \quad T={\frac {B}{A-\log _{10}p}}-C}$

of

${\displaystyle \ln p=A-{\frac {B}{C+T}}\quad \Rightarrow \quad p=e^{\left(A-{\frac {B}{C+T}}\right)}\quad \Rightarrow \quad T={\frac {B}{A-\ln p}}-C}$

Waar:

• ${\displaystyle p}$ = Dampdruk in absolute druk
• ${\displaystyle T}$ = Temperatuur
• ${\displaystyle A}$ , ${\displaystyle B}$ en ${\displaystyle C}$ is komponentspesifieke konstantes.

1 atm = 101.325 kPa = 760 mm Hg = 1.01325 bar

1 bar = 100 kPa

Die volgende tabel gee die konstantes vir water:

	A	B	C	T min. °C	T maks °C	Vergelyking
Water	8.07131	1730.63	233.426	1	100	${\displaystyle \log _{10}p=A-{\frac {B}{C+T}}}$ , p in mm Hg en T in °C
Water	8.14019	1810.94	244.485	99	374	${\displaystyle \log _{10}p=A-{\frac {B}{C+T}}}$ , p in mm Hg en T in °C
Water	11.449	3631.1	217.09	1	150(?)	${\displaystyle \ln p=A-{\frac {B}{C+T}}}$ , p in bar en T in °C

Hierdie moet dus ooreenstem met stoomtabelle.

Die konstantes vir etanol:

	A	B	C	T min. °C	T max °C	Vergelyking
Ethanol	8.20417	1642.89	230.300	-57	80	${\displaystyle \log _{10}p=A-{\frac {B}{C+T}}}$ , p in mm Hg en T in °C
Ethanol	7.68117	1332.04	199.200	77	243	${\displaystyle \log _{10}p=A-{\frac {B}{C+T}}}$ , p in mm Hg en T in °C

Die Antoinevergelyking kan ook soos volg omgeskakel wordː

${\displaystyle \log p=A-{\frac {B}{C+T}}}$

${\displaystyle {\frac {B}{C+T}}=A-\log p}$

${\displaystyle C+T={\frac {B}{A-\log p}}}$

${\displaystyle T={\frac {B}{A-\log p}}-C}$

Hierdie artikel is ’n saadjie. Voel vry om Wikipedia te help deur dit uit te brei.