2019 Murray Trophy – Glasgow – Doubles

Gerard Granollers and Guillermo Olaso were the defending champions[1] but chose not to defend their title.

Glasgow – Doubles
2019 Murray Trophy – Glasgow
Final
ChampionsBelgium Ruben Bemelmans
Germany Daniel Masur
Runners-upUnited Kingdom Jamie Murray
Australia John-Patrick Smith
Score4–6, 6–3, [10–8]
Events
SinglesDoubles
← 2018 ·Murray Trophy – Glasgow· 2020 →

Ruben Bemelmans and Daniel Masur won the title after defeating Jamie Murray and John-Patrick Smith 4–6, 6–3, [10–8] in the final.

Seeds

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Draw

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First roundQuarterfinalsSemifinalsFinal
1 J Murray
J-P Smith
66
WC Marshall Tutu
David Wright
421 J Murray
J-P Smith
66
Alt A Çelikbilek
C İlkel
7778Alt A Çelikbilek
C İlkel
34
H Heliövaara
E Ruusuvuori
65661 J Murray
J-P Smith
66
4 K Drzewiecki
S Walków
36[10] M Gengel
R Ramanathan
23
WC L Johnson
Mark Whitehouse
63[3]4 K Drzewiecki
S Walków
46[3]
M Gengel
R Ramanathan
779 M Gengel
R Ramanathan
63[10]
S Clayton
L Glasspool
5671 J Murray
J-P Smith
63[8]
N Kuhn
J Rodionov
w/o R Bemelmans
D Masur
46[10]
G Blancaneaux
A Rinderknech
N Kuhn
J Rodionov
R Bemelmans
D Masur
776 R Bemelmans
D Masur
w/o
3 A Göransson
S Verbeek
624 R Bemelmans
D Masur
64[11]
J Ocleppo
R Ortega Olmedo
6452 N Lammons
A Šančić
46[9]
Q Halys
M Martineau
777 Q Halys
M Martineau
42
R Gonzales
A Siljeström
4632 N Lammons
A Šančić
66
2 N Lammons
A Šančić
677

References

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  1. ^ "Britain's Jonny O'Mara & Scott Clayton lose Glasgow Trophy doubles final to Spanish duo". May 6, 2018 – via www.bbc.com.