1998 Bournemouth International – Doubles

The 1998 Bournemouth International was a men's tennis tournament played on Clay in Bournemouth, Great Britain that was part of the International Series of the 1998 ATP Tour. It was the third edition of the tournament and was held from 14 September – 20 September.

Doubles
1998 Bournemouth International
Final
ChampionsUnited Kingdom Neil Broad
Zimbabwe Kevin Ullyett[1]
Runners-upAustralia Wayne Arthurs
Spain Alberto Berasategui
Score7–6, 6–3
Events
Singlesmenwomen
Doublesmenwomen
← 1997 ·Bournemouth International· 1999 →

Seeds edit

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

Draw edit

Key edit

Finals edit

First roundQuarterfinalsSemifinalsFinal[1]
1 D Adams
D Macpherson
66
M Ondruska
C Wilkinson
221 D Adams
D Macpherson
67
M Maclagan
D Sapsford
77 M Maclagan
D Sapsford
46
P Kilderry
S Noteboom
651 D Adams
D Macpherson
63
4 W Arthurs
A Berasategui
664 W Arthurs
A Berasategui
76
C Brandi
V Santopadre
234 W Arthurs
A Berasategui
266
M Barnard
A Olhovskiy
366 M Barnard
A Olhovskiy
633
B Cowan
T Spinks
6434 W Arthurs
A Berasategui
63
M Kohlmann
L-A Wahlgren
662 N Broad
K Ullyett
76
D del Río
S Groen
33 M Kohlmann
L-A Wahlgren
566
3 C Haggard
J Waite
3673 C Haggard
J Waite
723
J Burillo
M-K Goellner
645 M Kohlmann
L-A Wahlgren
645
D Bowen
E Taino
6272 N Broad
K Ullyett
467
J Balcells
T Carbonell
066 D Bowen
E Taino
662
2 N Broad
K Ullyett
6772 N Broad
K Ullyett
376
F Browne
M Rodríguez
755

References edit

  1. ^ a b "1998 Bournemouth". International Tennis Federation. Archived from the original on 3 January 2015. Retrieved 3 January 2015.