1896 United States presidential election in Texas

The 1896 United States presidential election in Texas took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose 15 electors to the Electoral College, which selected the president and vice president.

1896 United States presidential election in Texas

← 1892November 3, 18961900 →
 
NomineeWilliam Jennings BryanWilliam McKinley
PartyDemocraticRepublican
AlliancePopulist
Home stateNebraskaOhio
Running mateArthur SewallGarret Hobart
Electoral vote150
Popular vote370,434167,520
Percentage68.00%30.75%

County Results

President before election

Grover Cleveland
Democratic

Elected President

William McKinley
Republican

Texas was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Four electors cast their vice presidential ballots for Thomas E. Watson.

Bryan would later win Texas again in both 1900 and 1908.

Results

edit
1896 United States presidential election in Texas[1]
PartyCandidateVotesPercentageElectoral votes
DemocraticWilliam Jennings Bryan370,43468.00%15
RepublicanWilliam McKinley167,52030.75%0
National DemocraticJohn M. Palmer5,0460.93%0
ProhibitionJoshua Levering1,7860.33%0
Totals544,786100.00%15
Voter turnout

See also

edit

Notes

edit

References

edit
  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results – Texas