1852 United States presidential election in Rhode Island

The 1852 United States presidential election in Rhode Island took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Rhode Island

← 1848 November 2, 1852 1856 →

Nominee Franklin Pierce Winfield Scott Party Democratic Whig Home state New Hampshire New Jersey Running mate William R. King William Alexander Graham Electoral vote 4 0 Popular vote 8,735 7,626 Percentage 51.37% 44.85%

County Results Pierce   40-50%   50-60% Scott   50-60%   60-70%

President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

Rhode Island voted for the Democratic candidate, Franklin Pierce, over the Whig Party candidate, Winfield Scott. Pierce won the state by a margin of 6.52%. This was the first of three times that the state voted differently than Massachusetts (along with 1972 and 1980).

This would be the final time until 1912 that a Democratic presidential candidate was able to win Rhode Island and the final time until 1928 that a Democratic candidate won a majority of the popular vote.