1852 United States presidential election in Alabama

1852 United States presidential election in Alabama
Pierce 40-50% 50-60% 60-70% 70-80% 80-90% 90-100%	Scott 40-50% 50-60% Troup 30-40% 40-50%
President before election; Millard Fillmore; Whig	Elected President ; Franklin Pierce; Democratic

The 1852 United States presidential election in Alabama took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Alabama voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Alabama by a margin of 26.77%.

Results

1852 United States presidential election in Alabama^[1]^[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William R. King of Alabama	26,881	60.89%	9	100.00%
	Whig	Winfield Scott of New Jersey	William A. Graham of North Carolina	15,061	34.12%	0	0.00%
	Southern Rights	George Troup	N/A	2,205	4.99%	0	0.00%
Total				44,147	100.00%	9	100.00%

^ "1852 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved December 2, 2017.
^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.

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